There seems to be a growing excitement about the “Supermoon” that is due to occur on 14 November 2016, when the Moon will be at its closest to Earth in this orbit, and closer than it has been at any time since 1948.
Sure the full moon will look big and bright this Sunday evening/Monday morning, but no more so than normal. It’ll be 14% larger and 30% brighter but your eyes and brain won’t see any difference from a normal full moon. It’s still worth a look – the moon is always a beautiful thing to see – but if you notice any difference in size or brightness, it’ll be your brain playing tricks on you. Maybe the power of suggestion or the Moon Illusion.
Read on to find out why it’s not any more super than normal…
The Moon orbits the Earth in an elliptical orbit, i.e. it is not perfectly circular, and so in each orbit there is a closest approach, called “perigee” and a furthest approach, called “apogee”.
At this month’s perigee the Moon will be 356,511km away from Earth. Closer than normal, sure but only 66km closer than the “Supermoon” that began all the hype back in 2011, so not that much closer.
Let’s start by comparing it to the Moon’s average distance from the Earth, which is ~385,000km. This perigee will be ~8% closer to the Earth than average. OK, that’s a bit closer, but not significantly so.
What about comparing it to the Moon’s average perigee distance, which is ~364,000km. So this “Supermoon” will be ~2% closer to the Earth than it is most months at perigee. Wow!
So what will this mean to you? Nothing at all. The Moon will be 14% bigger in the sky, but your eye won’t really be able to tell the difference. It will also be 30% percent brighter, but your eye will compensate for this too, so altogether this “Supermoon” will look exactly the same as it always does when it’s full.
As to all of those soothsayers claiming that there will be earthquakes and tidal waves. There very well might be, but they’ll be nothing at all to do with the Moon.
Supermoons aren’t all that rare. In fact they occur once every 13.5 months.
Thanks to Steve Bell at the UK Hydrographic Office for providing the calculations below: